1x^2-2x+17=0

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Solution for 1x^2-2x+17=0 equation:


Simplifying
1x2 + -2x + 17 = 0

Reorder the terms:
17 + -2x + 1x2 = 0

Solving
17 + -2x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-17' to each side of the equation.
17 + -2x + -17 + x2 = 0 + -17

Reorder the terms:
17 + -17 + -2x + x2 = 0 + -17

Combine like terms: 17 + -17 = 0
0 + -2x + x2 = 0 + -17
-2x + x2 = 0 + -17

Combine like terms: 0 + -17 = -17
-2x + x2 = -17

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -17 + 1

Reorder the terms:
1 + -2x + x2 = -17 + 1

Combine like terms: -17 + 1 = -16
1 + -2x + x2 = -16

Factor a perfect square on the left side:
(x + -1)(x + -1) = -16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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